Question 618666
4^(6x-1)=5^(x+4) 
take the log of both sides:
log(4^(6x-1))= log(5^(x+4)) 
(6x-1)log(4)= (x+4)log(5) 
(6x)log(4) - log(4) = xlog(5)+4log(5) 
(6x)log(4) = xlog(5)+4log(5)-log(4) 
(6x)log(4)-xlog(5) = 4log(5)-log(4) 
x[6log(4)-log(5)] = 4log(5)-log(4) 
x = [4log(5)-log(4)] / [6log(4)-log(5)]
x = 2.1938 / 2.9134
x = 0.753