Question 618534
1. <Ais twice as large as its complement<B
Equations:
A = 2B
A + B = 90
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Substitute for "A" and solve for "B":
2B + B = 90
3B = 90
B = 30 degrees
So A = 2B = 60 degrees
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2. <A is half as large as its complement,<B
Equations:
A = (1/2)B
A + B = 90
Substitute for "A: and solve for "B":
(1/2)B + B = 90
3/2 B = 90
B = (2/3)90 = 60
So A = 30
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cheers,
Stan H.
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