Question 618477
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Hi,
3y^2+13y+14
Might recommend thinking about FOIL and working <u>backwards</u>, so to speak
F	I.  First terms  3y·y is 3y^2
O	    Outside terms 
I	    Inside terms  
L	II. Last terms 1·14 and 2·7 works for '14'
(3y ...)(y...)
(3y ...7)(y...2)   ||trying 7 and 2 (with the 2 going with the 3)
(3y + 7)(y + 2)    || Yes!!   7y + 6y = 13y
the more You do..the better you get