Question 618333
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Hi, Previously Posted
Last year, the personal best high jumps of track athletes in a nearby state 
were normally distributed with a mean of 205 cm and a standard deviation of{{{ 13 }}}cm.
P(205< X <231) = {{{.954/2 = .477}}}
For the normal distribution: 
one  standard deviation from the mean accounts for about 68.2% of the set 
{{{two}}} standard deviations from the mean account for about 95.4%
and three standard deviations from the mean account for about 99.7%.