Question 618297
log(base3)8+log(base3)(7-2x)=2
.
{{{log(3,8) + log(3,7-2x) = 2}}}
{{{log(3,8(7-2x)) = 2}}}
{{{8(7-2x) = 8^2}}}
{{{56-16x = 64 }}}
{{{-16x = 8 }}}
{{{x = 8/(-16) }}}
{{{x = 1/(-2) }}}
{{{x = -1/2 }}}