Question 618271
Hello, 
Let's write this out as:
sq rt(2x+4)=x-2
Square both sides:
2x+4=(x-2)^2
Expand this out:
2x+4=x^2-4x+4
Subtract 2x and 4:
0=x^2-6x
Factor:
x(x-6)
Solve for x:
x=0
x=6
check each answer to see if they work:
0 doesn't work
6 does. 
Make sense?
RJ
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