<PRE><B>Question 618130</B>
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You made your error at: *[tex \LARGE 9\sqrt{3x^7y^9}\ \neq\ 9y^3\sqrt{3x^7}]


because 2 goes into 9 four times with a remainder of one.


*[tex \LARGE y^9\ =\ y^8\,\cdot\,y], so *[tex \LARGE \sqrt{y^9}\ =\ \sqrt{y^8}\,\cdot\,\sqrt{y}\ =\ y^4\sqrt{y}]


Similarly


*[tex \LARGE \sqrt{x^7}\ =\ x^3\sqrt{x}]


Putting it all back together:  *[tex \LARGE 9x^3y^4\sqrt{3xy}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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