Question 618104
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi, 
A line through(2 , 1)meets the curve x^2- 2x - y=3 at A(-2 , 5) and at B
the line passing through (2,1) and (-2,5)
(2,1) and 
(-2,5)  m = -4/4 = -1
 y = -x + b
 1 = -2 + b     ||Using PT(2,1) to solve for b
  3 = b
 {{{y}}} = -x + 3   AND  x^2- 2x - y=3 or {{{y}}} = x^2- 2x - 3
  x^2-2x-3 = -x + 3
  x^2-x - 6 = 0
 (x-3)(x+2) = 0
  (x+2) = 0 {{{ x = -2}}} We have A(-2 , 5)
 (x-3) = 0  {{{ x = 3  }}}  B(3,0)      ||| {{{y}}} = -x + 3 
{{{drawing(300,300,   -6, 6, -6, 6, grid(1),

graph( 300, 300, -6, 6, -6, 6,0,-x+3,x^2- 2x - 3 ))}}}