Question 617682


{{{(x+2)^2=121}}} Start with the given equation.



{{{x+2=""+-sqrt(121)}}} Take the square root of both sides.



{{{x+2=sqrt(121)}}} or {{{x+2=-sqrt(121)}}} Break up the "plus/minus" to form two equations.



{{{x+2=11}}} or {{{x+2=-11}}}  Take the square root of {{{121}}} to get {{{11}}}.



{{{x=-2+11}}} or {{{x=-2-11}}} Subtract {{{2}}} from both sides.



{{{x=9}}} or {{{x=-13}}} Combine like terms.



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Answer:



So the solutions are {{{x=9}}} or {{{x=-13}}}.