Question 617459
Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function. 
f(x)= 2x^2-12x+20  (I assume you forgot the x in the lead term)
The vertex is? 
Line of symmetry is? 
Max/Mini value is? 
The value, f(3)=2 is? Max or Min?
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y=2x^2-12x+20
complete the square
y=2(x^2-6x+9)+20-18
y=2(x-3)^2+2
This is an equation of a parabola that opens upwards.
Its standard form: y=(x-h)^2+k, (h,k)=(x,y) coordinates of vertex.
For given equation:
vertex: (3,2)
line or axis of symmetry: x=3
f(3)=2 is min
see graph below:
 {{{ graph( 300, 200, -6, 5, -10, 10, 2x^2-12x+20) }}}