Question 617410
A quadratic equation will have two real solutions if its discriminant, {{{b^2-4ac}}}, is positive. IOW:
{{{b^2-4ac > 0}}}
Inserting our values for a and c:
{{{b^2-4(4)(49) > 0}}}
{{{b^2-784 > 0}}}
{{{b^2 > 784}}}
Since {{{28^2 = 784}}}, b can be any number greater than 28 <i>or less than -28!</i> As long as b > 28 or b < -28, there will be two real solutions to your equation. Just pick any two such numbers.<br>
There not <i>just</i> two possible values for b as the problem seems to suggest.