Question 617380
Plug in arbitrary values of x to generate corresponding values of y (note: y and f(x) are the same thing basically)


So when x = 0, for instance, y is 3^(0+1) = 3^1 = 3


So we have one point (0, 3)


When x = 1, y is 3^(1+1) = 3^2 = 9


giving us another point (2,9)


Do this for any set of x values. I'm going to use the x values that range from -2 to 2 to generate the table


<TABLE border = 1 cellpadding=10>
<TR>
  <TD> x</TD>
  <TD><center>y</center></TD>
</TR>
<TR>
  <TD>  -2</TD>
  <TD>0.33333</TD>
</TR>
<TR>
  <TD>  -1</TD>
  <TD>1</TD>
</TR>
<TR>
  <TD>   0</TD>
  <TD>3</TD>
</TR>
<TR>
  <TD>   1</TD>
  <TD>9</TD>
</TR>
<TR>
  <TD>   2</TD>
  <TD>27</TD>
</TR>

</TABLE>


Now plot the points shown in the table above 


<img src="http://i150.photobucket.com/albums/s91/jim_thompson5910/Algebra%20dot%20com/6-3-2012-1.png">


Then draw a curve through them to graph {{{f(x) = 3^(x+1)}}}


<img src="http://i150.photobucket.com/albums/s91/jim_thompson5910/Algebra%20dot%20com/6-3-2012-2.png">


Note: because of our viewing window limitations, we don't see the point (2,27). To see this point, you would have to greatly distort the viewing window.