Question 617108
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Hi, 
preparing 500 ml of a 0.6% KCl solution from 10% KCl solution & distilled water {{{x}}}
         Water  = Water
 {{{  x + .90(500-x) = .94*500ml}}}
          {{{x = .04*500/.1}}}
               x = 200ml of distilled water needs to be added