Question 56995
find the inverse of the matrix
[-4 3]
[-3 2]= A SAY
DETERMINANT OF A =|A|=(-4)(2)-(3)(-3)=-8+9=1
MATRIX OF MINORS = AM =
|2,-3|
|3,-4|
MATRIX OF COFACTORS = ACF=
|2,3|
|-3,-4|
TRANSPOSE OF ABOVE = (ACF)'=
|2,-3|
|3,-4|
DIVIDE WITH |A| TO GET INVERSE
INVERSE OF A =(1/1)(ACF)'=
|2,-3|
|3,-4|
CHECK BY MULTIPLICATION .A*INVERSE A..WE GET 
|1,0|
|0,1|