Question 617078
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Hi
*[tex \large\ \ log_4(2x-7) + log_4(3x-3) = log_4(2x-7)(3x-3)= 4 ]
 4^4 = (2x-7)(3x-3)
  6x^2 -27x + 21 - 256 = 0
  3x^2 - 27x -235 = 0
{{{x = (27 +- sqrt( 6873))/(12) }}}
 x: -4.7,  9.2  (rounded to the nearest tenth)