Question 616959
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Let *[tex \LARGE x] represent the measure of one side of the square, then the length of the rectangle is *[tex \LARGE x\ +\ 3] and the width of the rectangle is *[tex \LARGE x\ -\ 2]


The area of the square is just *[tex \LARGE x^2]


And the area of the rectangle is *[tex \LARGE (x\ +\ 3)(x\ -\ 2)]


And these two areas are the same, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ =\ (x\ +\ 3)(x\ -\ 2)]


Expand the pair of binomials, collect like terms, and solve for *[tex \LARGE x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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