Question 616950
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He sells them for $5 each, so his revenue function is *[tex \LARGE R(x)\ =\ 5x] where *[tex \LARGE x] is the number sold.  His cost function is *[tex \LARGE C(x)\ =\ 2x\ +\ 35] because of the $2 per cone cost plus the $35 fixed rental cost.


Profit is revenue minus cost, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(x)\ =\ R(x)\ -\ C(x)\ =\ 5x\ -\ 2x\ -\ 35\ = 3x\ -\ 35]


So if you want the value of *[tex \LARGE P(x)] to be at least $200,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ -\ 35\ =\ 200]


Solve for *[tex \LARGE x] and round UP to the nearest whole number (because you can't sell a fraction of an ice cream cone).


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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