Question 616744
applying "log rules":
log[2](2x+15)-log[2](x)=3
log[2](2x+15)/(x)=3
(2x+15)/(x)= 2^3
(2x+15)/x = 8
2x+15 = 8x
15 = 6x
15/6 = x
5/2 = x