Question 616708
If light bulbs have lives that are normally distibuted with a mean of 2500 hours and a standard deviation of 500 hours, what percentage of light bulbs have a life less than 2500 hours?
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z(2500) = (2500-2500)/500 = 0
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Percent that have life < 2500 = P(z < 0) = 0.5000
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Cheers,
Stan H.
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