Question 616695
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Depends on whether any given student is allowed to be on more than one team.  If that is possible, the question cannot be answered with the given information. But if such is not allowed there will be 3 students for each of the 67 projects.  So you can add 3 + 3 + 3 + ... (67 times), or you could add 67 + 67 + 67, or you could just do it the simplest way:  Multiply 3 times 67.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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