Question 616625
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Hi, 
Find all of the real zeros of the polynomial function
f(x) = 3x^4 - 6x^3 + 4x^2 - 2x + 1   Note: x = 1 is a zero: 3-6+4-2+1 = 0
using synthetic division
1	3	-6	4	-2	1
		3	-3	1	-1
	3	-3	1	-1	0
(x-1)(3x^3 - 3x^2 + x-1)  Note: x = 1 is a zero of 3x^3 - 3x^2 + x-1
using synthetic division
1	3	-3	1	-1	
		3	0	1	
	3	0	1	0
(x-1)(x-1)(3x^2 - 1)
Real zeros is x = 1