Question 57070
L has y-intercept (0, -3) and is parallel to the line with equation y = 2/3X+1.
Write the equation of the line L satisfying the given geometric conditions.
:
The line that they gave you is in slope intercept form:{{{highlight(y=mx+b)}}}, where m=slope and (0,b)=y-intercept.
The slope of the line they gave you is:{{{y=highlight((2/3))x+1}}}, slope=m=2/3.
Parallel lines have the same slope, so the line you are writing the equation of has a slope of m=2/3 and a y-intercept of (0,b)=(0,-3)
Plug your values into the slope intercept form and you have the equation:
{{{y=highlight((2/3))x+highlight((-3))}}}
{{{highlight(y=(2/3)x-3)}}}
Happy Calculating!!!!