Question 616286
<ol><li>Draw a right triangle</li><li>Pick one of the acute angles. Let's call it angle A.</li><li>Label the side adjacent to angle A as 2 and the hypotenuse as 3. Since cos is adjacent over hypotenuse, we have just made cos(A) = 2/3</li><li>Since cot is adjacent over opposite, we need the opposite side. Use the Pythagorean Theorem to find the side opposite to angle A.</li><li>{{{cot(cos^(-1)(2/3))}}} will be adjacent over opposite, 2 over the answer from the previous step.</li><li>At this point you may have an acceptable answer. But it will have a square root in the denominator. You may want/need to rationalize the denominator. Just multiply the numerator and denominator by the square root in the denominator and simplify.</li></ol>