Question 616250
You were almost there, but on the right side you accidentally retyped the formula for their product rather than their sum i.e. instead of 7+n(n+2) you should have typed 7+n+(n+2) or just 7+n+n+2

So:
n(n+2)=n+n+2+7

{{{n^2+2n=2n+9}}}

Solve for n and put all numbers containing n to the left (remember to change the sign if moved):

{{{n^2+2n-2n=9}}}

{{{n^2=9}}}

n=3

so if n=3 this is the first integer and the second is 5.