<PRE><B>Question 616096</B>
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}&lt;P&gt;
a is the coefficient of the squared element, b is the coefficient of the variable (x or in this case r), and c is the constant.&lt;P&gt;
{{{3r^2 - 6r = -3}}} | First move the constant to the left by adding 3 to both sides.&lt;P&gt;
{{{3r^2 - 6r + 3 = 0}}} | Factor out any common factor.  In this case it&#39;s 3.&lt;P&gt;
{{3{r^2 - 2r + 1 = 0}}}  | The removed factor drops because 3 = 0 is never true.&lt;P&gt;
{{{r^2 - 2r + 1}}} | Now apply the quadratic formula.&lt;P&gt;
{{{(2 +- sqrt( (-2)^2-4*1*1 ))/(2*1) }}} = {{{(2 +- sqrt( 4-4 ))/2 }}} = &lt;P&gt;
{{{2/2 = 1}}}&lt;P&gt;
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