Question 57032
{{{ 2x/(x^2+x-6) - 3/ (x+3) + 1/(x-2) }}}
Factor the denominator of the first fraction
{{{ 2x/(x+3)(x-2) - 3/ (x+3) + 1/(x-2) }}}
Multiply the 2nd fraction by {{{ (x-2)/(x-2) }}} and the 3rd by {{{ (x+3)/(x+3) }}}
{{{ 2x/(x+3)(x-2) - 3(x-2)/(x+3)(x-2) + 1(x+3)/(x-2)(x+3) }}}
With the denominators all the same ... combine the numerators
{{{ (2x-3(x-2)+1(x+3))/(x+3)(x-2) }}}
Distibute through the numerator
{{{ (2x-3x+6+1x+3)/(x+3)(x-2) }}}
Combine the X terms in the numerator
{{{ (6+3)/(x+3)(x-2) }}}
Combine the constants
{{{ 9/(x+3)(x-2) }}}