Question 616104
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Hi, 
In General {{{A = P(1+r/n)^nt}}}
A = Accumulated Amount $4075
P= principal = $4000
r= annual rate = r
n= periods per year = 1 
t= years = 3 
{{{A/ P = 1.01875 =  (1+r)^3}}}
    log(1.01875) = 3log(1+r)
    log(1.01875)/3 = .0027 =  log(1+r)
             {{{10^(.0027) = 1+r}}}
                     .0062 = r  OR  Interest rate is .62%