Question 56973
*[invoke plot_any_graph "(4/3)x+3", -10, 10, -10, 10, 300, 300]

That's how the graph would look.  To do the X/Y table, just fill in the given values of x and solve, as shown below:

X  Y
-5 (4/3*-5)+3=-6 2/3+3 = -3 2/3
-4 (4/3*-4)+3=-5 1/3+3 = -2 1/3
-3 (4/3*-3)+3=-4+3 = -1
-2 (4/3*-2)+3=-2 2/3+3=1/3
-1 (4/3*-1)+3=-1 1/3+3=1 2/3
0  (4/3*0)+3=0+3=3
1  (4/3*1)+3=1 1/3+3=4 1/3
2  (4/3*2)+3=2 2/3+3=5 2/3
3  (4/3*3)+3=4+3=7
4  (4/3*4)+3=5 1/3+3=8 1/3
5  (4/3*5)+3=6 2/3+3=9 2/3