Question 615951
If a bullet is shot straight up with an initial velocity of 48 feet per second, its height s after t seconds is given by the equation s=48t-16t^2 Find the time it takes for the bullet to return to Earth.
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When the bullet hits the earth it's height is 0.
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Solve -16t^2 + 48t = 0
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Factor:
-16t(t - 3) = 0
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Positive solution:
t = 3 seconds
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Cheers,
Stan H.
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