Question 615765
interval:(0 to π)
solve the equation 
√3 cscx-2= 0
cscx=2/√3
1/cosx=2/√3
cosx=√3/2
x=π/6
.. 
Solve the equation 
tanx+ √3 = 0
tanx=-√3
x=2&#960;/3 (reference angle in quadrant II where tan<0)