Question 57021
3y=-10-5x
3x+5y=-6
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1st: 5x+3y=-10
2nd: 3x+5y=-6
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Multiply 1st by 3 ; Multiply 2nd by 5 to get:
3rd: 15x+9y=-30
4th: 15x+25y=-30
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Subtract 3rd from 4th to get:
16y=0
y=0
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Substitute in 1st to solve for y:
5x+0=-10
x=-2
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Check the answer in 2nd:
3(-2)+5(0)=-6
-6=-6
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So the solution of the system 
is x=-2, y=0
Cheers,
Stan H.