Question 615839
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*[tex \LARGE P(R)] is the probability of a red card.  Since half of the cards are red, *[tex \LARGE P(R)\ =\ \frac{13}{26}].  Red card outcome: *[tex \LARGE -1.00]


*[tex \LARGE P(BN)] is the probability of a black number card:  There are 18 black cards numbered 2 through 9 out of 52 cards.  *[tex \LARGE P(B)\ =\ \frac{9}{26}].  Black number outcome:  *[tex \LARGE +0.50]


*[tex \LARGE P(BF)] is the probability of a black face card:  There are 6 black face cards out of 52 cards.  *[tex \LARGE P(BF)\ =\ \frac{3}{26}].  Black face outcome:  *[tex \LARGE +1.00]


*[tex \LARGE P(BA)] is the probability of a black ace:  There are 2 black aces out of 52 cards.  *[tex \LARGE P(BA)\ =\ \frac{1}{26}].  Black ace outcome *[tex \LARGE +2.00]


Multiply each probability by the associated outcome value, then add up the expected values of each outcome.  Add 'em up.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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