Question 615604
The system of equations
{{{system(z-y = 30,z + y = 32)}}}
can be solved in many different ways.
Since the value of y is needed, you do not need a full solution.
You need to get a way to answer the question as quickly as possible.
I would multiply the first equation times (-1),
getting {{{-z+y=-30}}} and I would add the second equation to that, getting
{{{z+y-z+y=32-30}}} --> {{{2y=2}}} --> {{{highlight(y=1)}}}
So, the quantity in column B is 1, and since the quantity in column A is 2,
the quantity in column A is greater.