Question 615140
inverse the x and y and we get {{{x=1/2*sqrt(y-3)+5}}} and solve for y and we get 
{{{(x+5)=1/2*sqrt(y-3)}}} then {{{2(x+5)=sqrt(y-3)}}} then {{{(2x+10)^2=(y-3)}}} and {{{(2x+10)^2+3=y}}}