<PRE><B>Question 615245</B>
3x = 8y + 11
x + 6y - 8 = 0
put both equations into standard form
3x - 8y = 11
x + 6y = 8
:
multiply the 2nd equation by 3, subtract the 1st equation
3x + 18y = 24
3x - 8y = 11
--------------subtraction eliminates x, find y
0  + 26y = 13
26y = 13
y = 13/26
y = .5
:
We can find x using the equation x + 6y = 8, replace y with .5
x + 6(.5) = 8
x + 3 = 8
x = 8 - 3
x = 5
:
We can check out solution of x=5, y=.5 in the original 1st equation
3x = 8y + 11
replace x and y
3(5) = 8(.5) + 11
15 = 4 + 11</PRE>