Question 615206
d + q + h = 24


10d + 25q + 50h = 545 ___ 2d + 5q + 10h = 109


d = q + 5


substituting ___ (q + 5) + q + h = 24 ___ 2q + h = 19 ___ 20q + 10h = 190


substituting ___ 2(q + 5) + 5q + 10h = 109 ___ 7q + 10h = 99


subtracting equations (to eliminate h) ___ 13q = 91


solve for q, then substitute back to find d and h