Question 615028
North Avenue is 32 feet wide when it ends at Main Street.
 A 68 foot long diagonal crosswalk allows pedestrians to cross Main Street to or from either corner of North Avenue.
 Determine the width of Main Street.
:
This is a pythag problem; a^2 + b^2 = c^2
Where
a = 32 ft, width of n. ave
b = width of main street
c = 68 ft cross walk
:
32^2 + b^2 = 68^2
b^2 = 68^2 - 32^2
b = {{{sqrt(68^2 - 32^2)}}}
b = 60 ft is the width of Main