Question 615044
The length of one leg of a right triangle is 10 ft. The length of the hypotenuse is 2 feet longer than the other leg. Find the length of the hypotenuse and the other leg.
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Let the length of the 2nd leg be "x".
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(x+2)^2 = x^2 + 10^2
x^2 + 4x + 4 = x^2 + 100
4x = 96
x = 24
The length of the hypotenuse is x+2 = 26 ft.
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The length of the other leg is x = 24 ft.
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Cheers,
Stan H.