Question 614953
The base 12 number 973 in base 10 is equal to {{{9 * 12^2 + 7 * 12^1 + 3 * 12^0 = 1383}}}.


Each digit, or whatever it is called in base 12 because digit is usually used to refer to base 10 (decimal) numbers, is equal to {{{v * B^(n-1)}}} where v is the value, or magnitude, of the number at the nth digit from the right and B is the base, or radix, of the number system.


For example, in base 10, or decimal numbers, the number 742 means:

={{{7 * 10^2 + 4 * 10^1 + 2 * 10^0}}}
={{{700 + 40 + 2}}}

Which is 742 in base 10.


Now for a more interesting example, base 2, or binary, numbers consist of only the characters 0 and 1, but numbers are formed in exactly the same way as any other numeric base. For example:


10110   in base 2 is equal to:


{{{1 * 2^4 + 0 * 2^3 + 1 * 2^2 + 1 * 2^1 + 0 * 2^0}}}
={{{16 + 0 + 4 + 2 + 0}}}
=22 in base 10.


So your base 12 number is constructed in the same way:

973 base 12
= {{{9*12^2 + 7*12^1 + 3 * 12^0}}}
= 1296+84+3
= 1383 in base 10.