<PRE><B>Question 614925</B>
10 PEOPLE ARE RANDOMLY SEATED IN A ROW OF 10 CHAIRS. jOE AND jIM ARE IN A GROUP OF 10. wHAT IS THE PROBABILITY JOE AND JIM ARE SEATED ON THE ENDS?
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# of ways to succeed: 
end seats: 2 ways
between seats: 8!
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succeed in 2*8! ways
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# of possible outcomes: 10!
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Probability = (2*8!)/10! = 2/(10*9) = 1/45
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Cheers,
Stan H.
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