Question 614606
First of all, only equations or inequalities are solved. What you have is called an expression. Expressions are simplified.<br>
To simplify a square root, you look for perfect square factors of the radicand. ("Radicand" is the name for the expression inside a radical.) SO we look for perfect square factors of {{{50h^15}}}:
{{{sqrt(50h^15)}}}
{{{sqrt(25*h^2*h^2*h^2*h^2*h^2*h^2*h^2*2h)}}}
Since the radicand is all multiplication, I have used the Commutative Property to rearrange the order of the factors so that all the perfect squares are in front. Note also how I "lumped together" the factors that are not perfect squares, 2h. Neither of these are necessary but I find that it makes the rest of the simplifying a little easier.<br>
Next we use a property of all radicals (including square roots), {{{root(a, p*q) = root(a, p)*root(a, q)}}}, to separate all the perfect square factors into their own "personal" square roots:
{{{sqrt(25)*sqrt(h^2)*sqrt(h^2)*sqrt(h^2)*sqrt(h^2)*sqrt(h^2)*sqrt(h^2)*sqrt(h^2)*sqrt(2h))}}}<br>
Now simplify the square roots of the perfect squares:
{{{5*h*h*h*h*h*h*h*sqrt(2h))}}}
which simplifies to:
{{{5h^7*sqrt(2h))}}}
This is your simplified expression.<br>
P.S. The could be done a little faster if you are good with exponents:
{{{sqrt(50h^15)}}}
{{{sqrt(25*(h^7)^2*2h)}}}
{{{sqrt(25)*sqrt((h^7)^2)*sqrt(2h)}}}
{{{5h^7*sqrt(2h))}}}