Question 614579
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Hi,
what is the general form of the equation of a circle below
 (x-4)^2+y^2=16 
1)x^2+y^2-8x-16=16
 2)x^2+y^2-8x+16=16
 3)x^2+y^2-8x=0    || (x-4)^2 - 16 + y^2 = 0  or (x-4)^2 + y^2 = 16
 4)x^2+y^2+8x=0