Question 614586
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
write the equation of a circle ,in standard form, whose endpoints of its diameter:
 (-3,2) and 
 (3,-6)   Midpoint = (0,-2) and radius = {{{(1/2)sqrt( (-6)^2 + 8^2))}}} = 5
 equation of a circle:  {{{ x^2 + (y+2)^2 = 5^2}}}
Note:
D = {{{sqrt ((x[1]-x[2])^2+(y[1]-y[2])^2))}}}
Midpoint Pt(x,y):  ( {{{(x[1] + x[2])/2}}}, {{{(y[1] + y[2])/2  )}}})