Question 614561
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The sum of the logs is the log of the product, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \log\left(\sqrt{x}\right)\ +\ \log\left(\sqrt{x}\right)\ =\ \log\left(\sqrt{xy}\right)]


Two log functions to the same base are equal if and only if their arguments are equal, hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ \frac{x\ +\ y}{5}\ =\ \sqrt{xy}]


Multiply both sides by 5.  Square both sides.  Add *[tex \LARGE -2xy] to both sides.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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