Question 614535
{{{2x-3y=7}}}
{{{x-4y=2}}}


The first step is to multiply the 2nd equation by 2.
This is because in order to solve it, you must cancel out one of the variables.
By multiplying the 2nd equation by 2, you can subtract the new equation (from multiplying the 2nd equation by 2) from the 1st equation, and get 0x. This leaves you with only y. You can then solve for y, and then plug y back into an equation with x and find x.


{{{2x-3y=7}}}
{{{x-4y=2}}}


Multiply the 2nd equation by 2
({{{x-4y=2}}})x2
{{{2x-8y=4}}}


Subtract this from the first equation
{{{2x-3y=7}}}
{{{2x-8y=4}}}
-------
{{{5y=3}}}


Solve for y
{{{5y=3}}}
{{{y=3/5}}}


Plug y back into an equation with x
{{{x-4y=2}}}
{{{x-4(3/5)=2}}}
{{{x-12/5=2}}}
{{{x=2+12/5}}}
{{{x=22/5}}}