Question 614379
Two numbers are such that the ratio between them is 3:5.
If each is increased by 10, the ratio between the new numbers so formed is 5:7.
find the original numbers.
:
Let x = the multiplier
then
3x = one number
5x = the other number
:
"If each is increased by 10, the ratio between the new numbers so formed is 5:7."
{{{((3x+10))/((5x+10))}}} = {{{5/7}}}
Cross multiply
5(5x+10) = 7(3x+10)
:
25x + 50 = 21x + 70
25x - 21x = 70 - 50
4x = 20
x = 20/4
x = 5 is the multiplier
then
3(5) = 15 is the 1st number
5(5) = 25 is the 2nd number