Question 614467
Find all points (x,y) which lie on a circle with center (2,6) and radius of 5 if it's [sic] x-coordinate is twice its y coordinate. Only an algebraic solution is accepted. I can plot this with points using the center and radius but I just can't figure it out algebraicly.
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{{{(x-2)^2 + (y-6)^2 = 25}}}
x = 2y
Sub for x
{{{(2y-2)^2 + (y-6)^2 = 25}}}
{{{5y^2 - 20y + 15 = 0}}}
{{{y^2 - 4y + 3 = 0}}}
y = 1, y = 3
--> (2,1) & (6,3)