Question 614300
Find the solution(s) on the interval 0 &#8804; theta<2(pi)
2sin^2&#1012; + sin&#1012; = 0
2*2sinxcosx+sinx=0
sinx(4cosx+1)=0
sinx=0
x=0 and &#960;
or
4cosx+1=0
cosx=-1/4
x&#8776;1.823 and 4.965