Question 614208
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Hi, 
16 Blue , 9 Red ,13 Green ,9 Yellow , 11 Orange, 8 Brown. {{{66}}} M&Ms in all.
Choose one M&M at random 
a) P(Blue) = 16/66 = 8/33            
b) P(Red 'or' Brown) = 9/66 + 8/66 = 17/66
Choose Two M&M'S without replacement 
a) P(Blue then Green) = {{{(16/66)(13/65) }}}
b)P( Yellow then Yellow)= {{{(9/66)(8/65)}}}