Question 614168
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Hi, 
Susan started a job that paid $30,000 a year
Each year after the first, her salary increased by 4%. 
what is Susan's salary in his sixth year of employment...? 
{{{a[n] = a[1]*r^(n-1)}}}
{{{a[6] = 30000(1.04)^(5)}}} = $36,499.59
{{{sum( a[n], i=1, 6 ) = a[1]((1-r^n)/(1-r))}}} 
 {{{30000((1-(1.04)^6)/(-.04))}}} = $198,989.26